urllib2가 작동하지 않는 이유는 무엇입니까? http_open

파이썬 2.6.5가 설치된 우분투 10.04 32 비트 시스템에 3 개의 다른 파이썬 스크립트를 설치했습니다.

이들 모두는 urllib2를 사용하며 항상이 오류가 발생합니다.

urllib2.URLError : 왜 그렇습니까?

예 :

>>> import urllib2
>>> response = urllib2.urlopen("http://www.google.com")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.6/urllib2.py", line 126, in urlopen
    return _opener.open(url, data, timeout)
  File "/usr/lib/python2.6/urllib2.py", line 391, in open
    response = self._open(req, data)
  File "/usr/lib/python2.6/urllib2.py", line 409, in _open
    '_open', req)
  File "/usr/lib/python2.6/urllib2.py", line 369, in _call_chain
    result = func(*args)
  File "/usr/lib/python2.6/urllib2.py", line 1161, in http_open
    return self.do_open(httplib.HTTPConnection, req)
  File "/usr/lib/python2.6/urllib2.py", line 1136, in do_open
    raise URLError(err)
urllib2.URLError: <urlopen error [Errno 110] Connection timed out>



>>> response = urllib2.urlopen("http://search.twitter.com/search.atom?q=hello&rpp=10&page=1")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.6/urllib2.py", line 126, in urlopen
    return _opener.open(url, data, timeout)
  File "/usr/lib/python2.6/urllib2.py", line 391, in open
    response = self._open(req, data)
  File "/usr/lib/python2.6/urllib2.py", line 409, in _open
    '_open', req)
  File "/usr/lib/python2.6/urllib2.py", line 369, in _call_chain
    result = func(*args)
  File "/usr/lib/python2.6/urllib2.py", line 1161, in http_open
    return self.do_open(httplib.HTTPConnection, req)
  File "/usr/lib/python2.6/urllib2.py", line 1136, in do_open
    raise URLError(err)
urllib2.URLError: <urlopen error [Errno 110] Connection timed out>

최신 정보:

$ ping google.com
PING google.com (72.14.234.104) 56(84) bytes of data.
64 bytes from google.com (72.14.234.104): icmp_seq=1 ttl=54 time=25.3 ms
64 bytes from google.com (72.14.234.104): icmp_seq=2 ttl=54 time=24.6 ms
64 bytes from google.com (72.14.234.104): icmp_seq=3 ttl=54 time=25.1 ms
64 bytes from google.com (72.14.234.104): icmp_seq=4 ttl=54 time=25.0 ms
64 bytes from google.com (72.14.234.104): icmp_seq=5 ttl=54 time=23.9 ms
^C
--- google.com ping statistics ---
5 packets transmitted, 5 received, 0% packet loss, time 4003ms
rtt min/avg/max/mdev = 23.959/24.832/25.365/0.535 ms


$ w3m http://www.google.com
w3m: Can't load http://www.google.com.

$ telnet google.com 80
Trying 1.0.0.0...
telnet: Unable to connect to remote host: Connection timed out

업데이트 2 :

나는 집에 있고 라우터와 액세스 포인트를 사용하고 있습니다 :-. 그러나 방금 Firefox가 작동하지 않는다는 것을 알았습니다. 그러나 크롬, 시냅스 등은 작동합니다.

업데이트 3 :

>>> useragent = 'Mozilla/5.0 (X11; U; Linux x86_64; en-US) AppleWebKit/534.3 (KHTML, like Gecko) Ubuntu/10.04 Chromium/6.0.472.62 Chrome/6.0.472.62 Safari/534.3)'
>>> request = urllib2.Request('http://www.google.com/')
>>> request.add_header('User-agent', useragent )
>>> urllib2.urlopen(request)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.6/urllib2.py", line 126, in urlopen
    return _opener.open(url, data, timeout)
  File "/usr/lib/python2.6/urllib2.py", line 391, in open
    response = self._open(req, data)
  File "/usr/lib/python2.6/urllib2.py", line 409, in _open
    '_open', req)
  File "/usr/lib/python2.6/urllib2.py", line 369, in _call_chain
    result = func(*args)
  File "/usr/lib/python2.6/urllib2.py", line 1161, in http_open
    return self.do_open(httplib.HTTPConnection, req)
  File "/usr/lib/python2.6/urllib2.py", line 1136, in do_open
    raise URLError(err)
urllib2.URLError: <urlopen error [Errno 110] Connection timed out>

답변

먼저 시도 할 수있는 한 가지 테스트는 네트워크를 격리하는 것입니다.

시작 python -m SimpleHTTPServer하면 포트 8000에서 수신 대기하는 현재 디렉토리에 간단한 웹 서버가 생성됩니다.

그런 다음 테스트 할 수 있습니다.

>>> import urllib2
>>> response = urllib2.urlopen("http://localhost:8000")
>>> response.msg
'OK'

이렇게하면 문제가 파이썬인지 또는 네트워크 문제가 있는지 알 수 있습니다 (사례로 생각됩니다).

답변