임의 비밀번호와 일반 비밀번호 Github에는 가장 일반적인 10,000

Github에는 가장 일반적인 10,000 개의 비밀번호 목록 이 있습니다. 또한 나만의 임의 비밀번호 목록을 생성했습니다 .

당신의 임무는 두 목록의 차이점을 식별하는 것입니다 (100 % 정확도).

따라서 프로그램은 문자열을 받아서 다음을 리턴해야합니다.

  1. 비밀번호가 공통 비밀번호 목록에있는 경우 정확한 값
  2. 비밀번호가 임의의 비밀번호 목록에있는 경우 잘못된 값
  3. 비밀번호가없는 경우 원하는 사항

관심있는 사람들을 위해 내 프로그램은 5-10 자 길이의 암호를 생성하며 각 문자는 소문자 또는 숫자입니다.

참고 :이 비밀번호를 안전한 곳에 사용해서는 안됩니다. 내 세대 알고리즘은 전혀 안전하지 않으며 결과는 모두가 볼 수 있도록 온라인에 게시됩니다



답변

CJam, 2,262 908 620 512 503 바이트

0000000: 6c3a4c412c73277b2c39373e2b3a422d2c4c4c65752e3d65  l:LA,s'{,97>+:B-,LLeu.=e
0000018: 602c33653c5f333d5c5b513222011523a1d079937afebb7b  `,3e<_3=\[Q2"..#..y.z..{
0000030: 31a4ddf41a5e5038ef2aced9debeac5dc01fc4d27d809e0a  1....^P8.*.....]....}...
0000048: 2631e25b9e7d3314f1438f227b3235366233366242663d2f  &1.[.}3..C."{256b36bBf=/
0000060: 2b7d3a447e332205a4f76b4584be674d02001a36a250f949  +}:D~3"...kE..gM...6.P.I
0000078: 7bd0f1966deff2baab26a259813a0caa266155328064f0ee  {...m....&.Y.:..&aU2.d..
0000090: 20245dfab515c8faf39b08e80880c6e06c51728c57c153ec   $].............lQr.W.S.
00000a8: 9907a8365894bb8163bacd3a67173b50641c928f3ca87e89  ...6X...c..:g.;Pd...<.~.
00000c0: 81c1e95e5f049b61688fc7316e6a639876d00cdf4c01a100  ...^_..ah..1njc.v...L...
00000d8: 998bd12ccf3fb8ca61c89f5a57cedf8170b4b062653d947e  ...,.?..a..ZW...p..be=.~
00000f0: 9f6d5ba729db151b79151ae044cd6416274c73110e777172  .m[.)...y...D.d.'Ls..wqr
0000108: 22445132220133e9dcda9e224435224dc7621a0ae9224433  "DQ2".3...."D5"M.b..."D3
0000120: 220980cb1f885db429b742f47062cc1190767d82e6e956b7  ".....].).B.pb...v}...V.
0000138: 1de25dd9c2be7bf5224451322201c9167dd15a8c8cdd110f  ..]...{."DQ2"...}.Z.....
0000150: e956678cd6467ed95c22d7700c1d37a5b1ad94d3b3a3531e  .Vg..F~.\".p..7.......S.
0000168: 639ba99f27cde7e9c81c686adb874d6d5ac411d8d5e44363  c...'.....hj..MmZ.....Cc
0000180: deff8759ed48c97a32b5eeed5ef23be112773a0e0454e6a5  ...Y.H.z2...^.;..w:..T..
0000198: d064d43adf998c7050910c723616dccb5874a8b3640e39e0  .d.:...pP..r6...Xt..d.9.
00001b0: b7545841c7b3152d13ab3e83857530313cb737c799837a4b  .TXA...-..>..u01<.7...zK
00001c8: 396a39e68c9722443322d87648012832adde4e33e27615e2  9j9..."D3".vH.(2..N3.v..
00001e0: 4b6bf7e94bec9022445d3d7b4c5c23297d253a2b215e7c    Kk..K.."D]={L\#)}%:+!^|

공통 암호의 경우 양의 정수를 인쇄하고 다른 암호의 경우 0을 인쇄합니다.

확인

$ xxd -c 24 -g 24 testall.cjam
0000000: 714e257b3a4c412c73277b2c39373e2b3a422d2c4c4c6575  qN%{:LA,s'{,97>+:B-,LLeu
0000018: 2e3d65602c33653c5f333d5c5b513222011523a1d079937a  .=e`,3e<_3=\[Q2"..#..y.z
0000030: febb7b31a4ddf41a5e5038ef2aced9debeac5dc01fc4d27d  ..{1....^P8.*.....]....}
0000048: 809e0a2631e25b9e7d3314f1438f227b3235366233366242  ...&1.[.}3..C."{256b36bB
0000060: 663d2f2b7d3a447e332205a4f76b4584be674d02001a36a2  f=/+}:D~3"...kE..gM...6.
0000078: 50f9497bd0f1966deff2baab26a259813a0caa2661553280  P.I{...m....&.Y.:..&aU2.
0000090: 64f0ee20245dfab515c8faf39b08e80880c6e06c51728c57  d.. $].............lQr.W
00000a8: c153ec9907a8365894bb8163bacd3a67173b50641c928f3c  .S....6X...c..:g.;Pd...<
00000c0: a87e8981c1e95e5f049b61688fc7316e6a639876d00cdf4c  .~....^_..ah..1njc.v...L
00000d8: 01a100998bd12ccf3fb8ca61c89f5a57cedf8170b4b06265  ......,.?..a..ZW...p..be
00000f0: 3d947e9f6d5ba729db151b79151ae044cd6416274c73110e  =.~.m[.)...y...D.d.'Ls..
0000108: 77717222445132220133e9dcda9e224435224dc7621a0ae9  wqr"DQ2".3...."D5"M.b...
0000120: 224433220980cb1f885db429b742f47062cc1190767d82e6  "D3".....].).B.pb...v}..
0000138: e956b71de25dd9c2be7bf5224451322201c9167dd15a8c8c  .V...]...{."DQ2"...}.Z..
0000150: dd110fe956678cd6467ed95c22d7700c1d37a5b1ad94d3b3  ....Vg..F~.\".p..7......
0000168: a3531e639ba99f27cde7e9c81c686adb874d6d5ac411d8d5  .S.c...'.....hj..MmZ....
0000180: e44363deff8759ed48c97a32b5eeed5ef23be112773a0e04  .Cc...Y.H.z2...^.;..w:..
0000198: 54e6a5d064d43adf998c7050910c723616dccb5874a8b364  T...d.:...pP..r6...Xt..d
00001b0: 0e39e0b7545841c7b3152d13ab3e83857530313cb737c799  .9..TXA...-..>..u01<.7..
00001c8: 837a4b396a39e68c9722443322d87648012832adde4e33e2  .zK9j9..."D3".vH.(2..N3.
00001e0: 7615e24b6bf7e94bec9022445d3d7b4c5c23297d253a2b21  v..Kk..K.."D]={L\#)}%:+!
00001f8: 5e7c7d2524656070                                  ^|}%$e`p
$ echo $LANG
en_US
$ cjam testall.cjam < 10k-common-passwords.txt
[[9989 1] [4 2] [2 3] [3 5] [2 7]]
$ cjam testall.cjam < generated_passwords.txt
[[1000 0]]

답변

파이썬, 719 664 바이트

import re
lambda s:re.search(r"(?!.*([xvonkj]0|p[9q5]|i2|q[4rt]|xk|m8|jp|jg|4k|2n|0b|y.[xj7]|mnw|c.3|7.2|4wu|061|zt[ub]|r6[d8]|o.0|jd[be]|j[wz]o|hk[cj]|^(wb|wd|v3|ub|s2|s1|pb|ml|j5|hv|h1|g8|g6|ft|f4|94|0t)|(we|ha|93|80)4|(xj|x5|03|qa|fz|w)9|3[65]0|zbx|(w.|v|o.?|54)7|[th]82|ssg|g(lc|ij|v|1[34]|bx|bk)|wvf|uax|mss|uhl|306|4.[mr]|9p|rob$))^.*((^([14]?\D+|\D*\d+|\d{3}\D{5}|(?=^\D*\d\D*$).{6}|\D+4\D+|[1-4a-eqwr]+)|sx|[ekru]s|t4u|zx|[avy]y|x[prs]|w[mp2]|uz|tp|tn|sc|qq|qj|p[mov]|r[deq]|oo|n[4tu]|me|k[23c]|jf|[2ag]t|ed|bq|a1|3r|5g)$|\W|123|^(nc|tr|w0|sa|rj|q[bnqu]|ni|mo|mw|le|kc|ib|hz|g9|f0|cb|b9|8d|7k|6u|5w|3m|1q)|z.g|bo|em|x35|t.d|p.o|p39|mar|ki4|id8|ebk|53x)",s)

Retina 에서 이것을 테스트하는 데 약간의 어려움이 있으므로 지금은 Python입니다. lambda이름을 지정하고 단어 목록에서 실행 하여 테스트 하십시오.

>>> len([x for x in common if f(x)])
10000
>>> len([x for x in generated if f(x)])
0

그것은 매우 큰 정규 표현식이므로 골프를 잠시 중단합니다.


답변

배쉬-5324 바이트

gunzip -c rp.gz|grep $1|wc -l

여기서 rp.gz는 http://dl.tyzoid.com/rp.gz에 있습니다.

임의리스트에있는 경우 1을 리턴합니다. bash가 0을 truty 값으로 증발시키기 때문에 이것은 거짓입니다.


답변

하스켈, 8047 바이트

main=interact$show.flip notElem(words"viy130k57 d69z0 iz7q4d u26q3h 4mr6bhwa4 d36p5d 83554s 70r310py dz3js3 i1w86i0 2c4bk9 26w4kg52 u8i1g22ge 86k4br 875orut1 kw5786758 4k87v nfi5f2h9 x303978 43r4qb 963lnbs h5c1vq6s2 0iyv53vr2 nf5tmbp8 31ieq5xlh 9b450m ohv69d 5297m29 jvsxd20k fuha432 o8i84sh mss63 56vl8kzv8 73hh251 zr3r3zph 5f195v3kq 4o224g8 yi3y1lgi7 5ihcc t1krtr8w6 g7x9cuv4 128ov7 10adfe9 1p3lw 2523v xpj3h6z w2546kzx5 4042nle 0vv7i7ng xxzmf5vl efh601zby 19i0o63 8l20191 xm7e96pl 691p7m3p2 ksx29c2q3 auhli 7jq5e9e 786wo1q 1gwiaj7y8 3r19f26 x2nnr7 3u235s 076zr95m xzr32d 0lo70 v6o391 72pm08fo 79p1v9 uw98b 9mh7q3 2mh6bz a4qqw8d zve8z 790gkwc t975y 7d206t06 0zkvd9q0e y0cb34 9tltcs41w 079bp2y lwk12f 58gz4p 7lrkl io89he175 49dcu m2qg1 1ic76l kt9k9525i 6jwd8 4m9xwe86 3212janr r694ax 2raflx7s s26km575 n0z3hsdhj 9zl3x5 88c96968n 1lbw1v 20kri 799934a91 6c51846 61o78mjun 3d1yn 13113u8ev z22n5ni 0jxuc 79zwnl3tx xv4h4kz7 001n9 2u0f2 8msf6t g83r6v 81j4tt5e 20ucmaf j576783 v64ar 3u16pj83p r817zu6d xgc63 4y1rpo0 031606p 43q08m3x 1sg237d1n dt85c vg30a u4ge5t 4bv27l432 0612939 8glq6zo g64m0r4 593erv6 962a24u 94rop d28fs6k xy78efw3 yd0kyj1 y02rl 3n21q esg5y9m9 8408qpscw 5lapn9k26 4x1k27 7mb8054 4s1x7olv5 10s7726 00eib 84pu58e6 505l3s6 ldgx9e7d hv4d6u56s 5ren77w uf6pmf2 0sfum 1ik8mx vzqtj77 cvjc1ta us90844jb 84r0d4td plab52n 7946vj4l7 qy5gjtr 49lpq 4w49fm 44y0rh472 07jt8 1tju72 q0733u1 375ojd0 1t28s9ag1 ppj60t704 wi67b877 jgrrh388 ftvu98 h214l3x 3nirvrdu mrg14 52s65y 9f587 2629v os80p7 3h89mqk xt5845q9m 68h53w 8b3309g 16967k 38356nk 34oyt he3v5vn2 m1g2c8 8n324x6 2by0e7x 1a4mit7 ge91p60y b170o 9v5rys 6wq3959ue ed9u3 kd4wy1 c853gz k56gel09h 789ygx5pk 1f9f2 84fxtdx d02fdz9i 6gj4i4 6p8jtsax 3v38hkcs2 80090i 8084xb4m c4xv4x79 pilbux017 9m193zg5 qwq5o6x5 90cw69n96 n237351i cm40sj1x 3727d9p q0x74ityn 3ez6679 t7vs045 r7jg22xyr 3z34a96 miu8lm62 cpzjf226u vb2545x 4f9qg7sdq 2rf6t kq0ixi32n rjdeuj g8x5p3 d776c 4x1385 830nug s1tysl o679090 93kgz18 91pu8l n05i73 mdmq4c 31her5 6r10e0il i02np063 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2m3w8h2ee 110o27 w730108t 4547b0 0e998 d62io mjri4m90m 822xgu 7404u73i3 6g73d1 292uv351 789e6 f6721070g 5752261 y5l2i vh471uy 1p06933q o2l85722 axoz605ic yd97s 78whg y8eeb5b sr76mqe wc0855h6j 4ztui 4bc8n5 hvyuovxl4 0tifec 2coog5s6n j2mbd344h bgbx7 m7a4t2j77 vdc2d854 mizbxb2 1xj676 5oi49bw66 t451834gd 1xh7o t006va 6c0jy 126ly2n5 i432l5t61 myrou93w v0t5fi5s4 1zne2o rysfj8k 44x53c 9kk15 8938quif d6f7x 3nz3p cjg70t v309011 07nw947ey 6rc18 n11551so 24dtm5159 qpd4p40 f3794b9y9 8hcx5oo5 570bu cl442vxg l59bl10jx lj5gz00u b7tn6uu08 45m43uf53 t62861qf9 780288ew 3867o8p7 3k8uc we7zh sub593fof qxyi7 q634jlqz 9acjc 24v0eksmu ltx1crj 0y0b73qt 64c8yd 5hbes3 c791g97o2 tg9j2 8736l v2am0 4yq2yg943 193di7141 ss6xq y60lv92r 77b1v383 o9acsyje 163449n0 mnw167 2skcq u5z4v3i 4u70jc 8w872 42q9k44f fshyn004 qr1fa 59599zxbh g25wi69l 61vfy6 01474kb7 6mp11b 62t63e3l 198njo 673s491p ab8dr4qz 2s243 7hwz6lq79 d999oo3 6vsy1 6pf862 79x2dmq85 7q6q48i2 21g4mzy25 do85ib82x r0wb2 6zq2rmf 5q2jp41 bc60yv x18t30 5c0zt6m3 na80h6tc y5r6n o40r45v 0ufog 49w11ce0 10i3cbapw 606z0ti kowx5iro l59quc0 4t00o8")

이것은 압축 알고리즘을 위반하지 않고 알아낼 수있는 최선의 것으로 보입니다. 내가 사용하려는 언어 중 어느 것도 간단한 내장 압축 방법을 가지고 있지 않습니다.

“알고리즘”은 매우 간단합니다. 임의 암호 목록에 있는지 확인하고 False이면 False를, 그렇지 않으면 True를 반환하십시오.