7z zip을 추출하는 방법과 올바른 디렉토리 구조가 있습니까? Version 9.20

XXXhostXXX:temp XXXuserXXX$ ls -a dir1/
.   ..  a.txt   b.txt
XXXhostXXX:temp XXXuserXXX$ pwd
/Users/XXXuserXXX/temp
XXXhostXXX:temp XXXuserXXX$ 7z a -t7z dir1 dir1

7-Zip [64] 9.20  Copyright (c) 1999-2010 Igor Pavlov  2010-11-18
p7zip Version 9.20 (locale=utf8,Utf16=on,HugeFiles=on,4 CPUs)
Scanning

Creating archive dir1.7z

Compressing  dir1/a.txt
Compressing  dir1/b.txt

Everything is Ok
XXXhostXXX:temp XXXuserXXX$ ls
dir1    dir1.7z
XXXhostXXX:temp XXXuserXXX$ mkdir tmp
XXXhostXXX:temp XXXuserXXX$ mv dir1.7z tmp/.
XXXhostXXX:temp XXXuserXXX$ cd tmp/
XXXhostXXX:tmp XXXuserXXX$ ls
dir1.7z
XXXhostXXX:tmp XXXuserXXX$ 7z e dir1.7z

7-Zip [64] 9.20  Copyright (c) 1999-2010 Igor Pavlov  2010-11-18
p7zip Version 9.20 (locale=utf8,Utf16=on,HugeFiles=on,4 CPUs)

Processing archive: dir1.7z

Extracting  dir1/a.txt
Extracting  dir1/b.txt
Extracting  dir1

Everything is Ok

Folders: 1
Files: 2
Size:       58
Compressed: 216
XXXhostXXX:tmp XXXuserXXX$ ls
a.txt   b.txt   dir1    dir1.7z
XXXhostXXX:tmp XXXuserXXX$
XXXhostXXX:tmp XXXuserXXX$ ls -a dir1
.       ..

왜 마지막에? a.txt 과 b.txt ~에서 꺼냈다. dir1?

답변

시도해 볼 수있는 것처럼 보입니다. x 명령 대신 전자 . 예를 들어

7za x test.7z

나를 위해 일하고 전체 디렉토리 구조를 보존했습니다.

답변

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